25 mL of household bleach solution was mixed with 30 mL of 0.50 M KI and 10 mL of 4 N acetic acid. In the titration of the liberated iodine, 48 mL of 0.25 N Na2S2O3 was used to reach the end point. The molarity of the household bleach solution is

Question

25 mL of household bleach solution was mixed with 30 mL of 0.50 M KI and 10 mL of 4 N acetic acid. In the titration of the liberated iodine, 48 mL of 0.25 N Na2S2O3 was used to reach the end point. The molarity of the household bleach solution is (A) 0.24 M (B) 0.48 M (C) 0.024 M (D) 0.96 M

Tardigrade Admin · Accepted Answer

underset underset25 ml textBleachH2 O2+ underset underset30 ml0 . 5 M2 I-+ underset underset4 N (. 10 ml .)(. textfrom (CH)3 COOH .)2 H+ arrow I2 +2H2O ...(i) I2+ underset0 . 25 N (. 48 ml .)2 (Na)2 S2 O3 arrow (Na)2S4O6+2NaI ...(ii) m. mol of I2=(1/2) (m. Moles of Na2S2O3 ) =(1/2)× (.0.25× 48.)=6m.mol Using equation (i) 1 m. Mol of I2≡ 1 m. Mol of H2O2 m.mol of H2O2=6 m.mol Molarity of H2O2=(6/25)=0.24 M

Q. $25 m L$ of household bleach solution was mixed with $30 m L$ of $0.50 M$ $K I$ and $10 m L$ of $4 N$ acetic acid. In the titration of the liberated iodine, $48 m L$ of $0.25 N$ $N a_{2} S_{2} O_{3}$ was used to reach the end point. The molarity of the household bleach solution is

$0.24 M$

$0.48 M$

$0.024 M$

$0.96 M$

Q. 25mL of household bleach solution was mixed with 30mL of 0.50M KI and 10mL of 4N acetic acid. In the titration of the liberated iodine, 48mL of 0.25N Na2​S2​O3​ was used to reach the end point. The molarity of the household bleach solution is

0.24M

0.48M

0.024M

0.96M

Q. $25 m L$ of household bleach solution was mixed with $30 m L$ of $0.50 M$ $K I$ and $10 m L$ of $4 N$ acetic acid. In the titration of the liberated iodine, $48 m L$ of $0.25 N$ $N a_{2} S_{2} O_{3}$ was used to reach the end point. The molarity of the household bleach solution is

$0.24 M$

$0.48 M$

$0.024 M$

$0.96 M$