25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na+ and carbonate ions,CO2-3 are respectively (Molar mass of Na2CO3 = 106 g mol-1)

Question

25.3 g of sodium carbonate, Na2CO3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na+ and carbonate ions,CO2-3 are respectively (Molar mass of Na2CO3 = 106 g mol-1) (A) 0.477 M and 0.477 M (B) 0.955 M and 1.910 M (C) 1.910 M and 0.955 M (D) 1.90 M and 1.910 M

Tardigrade Admin · Accepted Answer

Molarity =(25.3 × 1000/106 × 250)=0.955 M Na 2 CO 3 longrightarrow 2 Na ++ CO 3-2 =2 × 0.9550 .955 M =1.910 M

Q. 25.3g of sodium carbonate, Na2​CO3​ is dissolved in enough water to make 250mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na+ and carbonate ions,CO32−​ are respectively (Molar mass of Na2​CO3​=106gmol−1)

0.477 M and 0.477 M

0.955 M and 1.910 M

1.910 M and 0.955 M

1.90 M and 1.910 M

Molarity =106×25025.3×1000​=0.955M Na2​CO3​⟶2Na++CO3−2​ =2×0.9550.955M =1.910M

Molarity $= \frac{25.3 \times 1000}{106 \times 250} = 0.955 M$
$N a_{2} C O_{3} ⟶ 2 N a^{+} + C O_{3}^{- 2}$
$= 2 \times 0.9550.955 M$
$= 1.910 M$