25.3 g of sodium carbonate, Na 2 CO 3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na +and carbonate ions, CO 32- respectively are (Molar mass of Na 2 CO 3=106 mol -1 )

Question

25.3 g of sodium carbonate, Na 2 CO 3 is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na +and carbonate ions, CO 32- respectively are (Molar mass of Na 2 CO 3=106 mol -1 ) (A) 0.477 M and 0.477 M (B) 0.955 M and 1.910 M (C) 1.910 M and 0.955 M (D) 1.90 M and 1.910 M

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<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/ad175061c2b60bf8c78e9a45fc5fecec-.png" /> ∴ [ Na +] =2 × 0.955 M =1.910 M [ CO 32-]=0.955 M

$0.477 M$ and $0.477 M$

$0.955 M$ and $1.910 M$

$1.910 M$ and $0.955 M$

$1.90 M$ and $1.910 M$

$∴ [N a^{+}] = 2 \times 0.955 M = 1.910 M$
$[C O_{3}^{2 -}] = 0.955 M$

Q. 25.3g of sodium carbonate, Na2​CO3​ is dissolved in enough water to make 250mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ion, Na+and carbonate ions, CO32−​ respectively are (Molar mass of Na2​CO3​=106mol−1 )

0.477M and 0.477M

0.955M and 1.910M

1.910M and 0.955M

1.90M and 1.910M

∴[Na+]=2×0.955M=1.910M [CO32−​]=0.955M

$0.477 M$ and $0.477 M$

$0.955 M$ and $1.910 M$

$1.910 M$ and $0.955 M$

$1.90 M$ and $1.910 M$

$∴ [N a^{+}] = 2 \times 0.955 M = 1.910 M$
$[C O_{3}^{2 -}] = 0.955 M$