245 mathrm~g impure sample of mathrmKClO3( mathrm~s) on heating gives 12 mathrm~g mathrmO2( mathrm~g) according to 2 mathrmKClO3( mathrm~s) arrow 2 mathrmKCl( mathrms)+3 mathrmO2( mathrm~g) Calculate % purity of sample?

Question

245 mathrm~g impure sample of mathrmKClO3( mathrm~s) on heating gives 12 mathrm~g mathrmO2( mathrm~g) according to 2 mathrmKClO3( mathrm~s) arrow 2 mathrmKCl( mathrms)+3 mathrmO2( mathrm~g) Calculate % purity of sample? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

2 textKClO text3 arrow 2 textKCl + 3 textO text2 Let the % purity = textx Mole of KClO3 = (245/122.5)× (x/100) = (2 x/100) Mole of O2 = (2 x/100)× (3/2) (2 x/100)× (3/2)× 32=12 (% purity of sample) textx text= text12 text.5

Q. $245 g$ impure sample of $KClO_{3} (s)$ on heating gives $12 g O_{2} (g)$ according to $2 KClO_{3} (s) \to 2 KCl (s) + 3 O_{2} (g)$ Calculate \% purity of sample?

$2 KClO_{3} \to 2 KCl + 3 O_{2}$

Let the % purity = $x$

Mole of $K Cl O_{3}$ = $\frac{245}{122.5} \times \frac{x}{100}$ = $\frac{2 x}{100}$

Mole of $O_{2}$ = $\frac{2 x}{100} \times \frac{3}{2}$

$\frac{2 x}{100} \times \frac{3}{2} \times 32 = 12$

(% purity of sample) $x = 12 .5$

Q. 245 g impure sample of KClO3​( s) on heating gives 12 gO2​( g) according to 2KClO3​( s)→2KCl(s)+3O2​( g) Calculate \% purity of sample?

2KClO3​→2KCl+3O2​ Let the % purity = x Mole of KClO3​ = 122.5245​×100x​ = 1002x​ Mole of O2​ = 1002x​×23​ 1002x​×23​×32=12 (% purity of sample) x=12.5

Q. $245 g$ impure sample of $KClO_{3} (s)$ on heating gives $12 g O_{2} (g)$ according to $2 KClO_{3} (s) \to 2 KCl (s) + 3 O_{2} (g)$ Calculate \% purity of sample?

$2 KClO_{3} \to 2 KCl + 3 O_{2}$

Let the % purity = $x$

Mole of $K Cl O_{3}$ = $\frac{245}{122.5} \times \frac{x}{100}$ = $\frac{2 x}{100}$

Mole of $O_{2}$ = $\frac{2 x}{100} \times \frac{3}{2}$

$\frac{2 x}{100} \times \frac{3}{2} \times 32 = 12$

(% purity of sample) $x = 12 .5$