200 V ac source is fed to series LCR circuit having XL = 50 Ω, XC = 50Ω and R = 25Ω. Potential drop across the inductor is

Question

200 V ac source is fed to series LCR circuit having XL = 50 Ω, XC = 50Ω and R = 25Ω. Potential drop across the inductor is (A) 100 V (B) 200 V (C) 400 V (D) 10 V

Tardigrade Admin · Accepted Answer

Here, Vrms = 200 V, XL=50 Ω, XC=50 Ω, R=25 Ω Impedance of the circuit, Z=√R2+(XL-XC)2 =√252+(50-50)2 =25 Ω Current in the circuit, Irms=(Vrms/Z) =(200 V/25 Ω) =8 A Voltage drop across the inductor is VL=IrmsXL =8 A×50 Ω =400 V

Q. $200 V$ ac source is fed to series $L CR$ circuit having $X_{L} = 50 Ω$ , $X_{C} = 50Ω$ and $R = 25Ω$ . Potential drop across the inductor is

$100 V$

$200 V$

$400 V$

$10 V$

Q. 200V ac source is fed to series LCR circuit having XL​=50Ω, XC​=50Ω and R=25Ω. Potential drop across the inductor is

100V

200V

400V

10V

Here, Vrms​=200V, XL​=50Ω, XC​=50Ω, R=25Ω Impedance of the circuit, Z=R2+(XL​−XC​)2​ =252+(50−50)2​ =25Ω Current in the circuit, Irms​=ZVrms​​ =25Ω200V​ =8A Voltage drop across the inductor is VL​=Irms​XL​ =8A×50Ω =400V

Q. $200 V$ ac source is fed to series $L CR$ circuit having $X_{L} = 50 Ω$ , $X_{C} = 50Ω$ and $R = 25Ω$ . Potential drop across the inductor is

$100 V$

$200 V$

$400 V$

$10 V$