Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
20 mL of methane is completely burnt using 50 mL of oxygen. The volume of the gas left after cooling to room temperature is
Q.
20
m
L
of methane is completely burnt using
50
m
L
of oxygen. The volume of the gas left after cooling to room temperature is
4770
210
KCET
KCET 2012
Hydrocarbons
Report Error
A
80 mL
6%
B
40 mL
17%
C
60 mL
13%
D
30 mL
64%
Solution:
∴
Volume of gas left after cooling
=
10
m
L
O
2
+
20
m
L
C
O
2
=
30
,
m
L
H
2
O
(
g
)
will be condense to
H
2
O
(
l
)
after cooling.
