20 ml of 0.2 M Al 2( SO 4)3 is mixed with 20 ml of 6.6 M BaCl 2, the concentration of Cl- ion in solution is

Question

20 ml of 0.2 M Al 2( SO 4)3 is mixed with 20 ml of 6.6 M BaCl 2, the concentration of Cl- ion in solution is (A) 0.2 M (B) 6.6 M (C) 0.02 M (D) 0.06 M

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/8f860643759ddb630e0e02bab6d18bd9-.png" /> 2 × 6.6 × 20=M2 ×[20+20] arrow Mixed with 20 mL of Al 2( SO 4)3 It increases volume but can't effect concentration of Cl -because it does not have Cl- M 2=(2 × 6.6 × 20/40)=6.6

Q. $20 m l$ of $0.2 M A l_{2} (S O_{4})_{3}$ is mixed with $20 m l$ of $6.6 M B a C l_{2}$ , the concentration of $Cl$ ion in solution is

0.2 M

6.6 M

0.02 M

0.06 M

$2 \times 6.6 \times 20 = M_{2} \times [20 + 20] \to$ Mixed with $20 m L$ of $A l_{2} (S O_{4})_{3}$
It increases volume but can't effect concentration of $C l^{-}$ because it does not have $C l^{-}$
$M_{2} = \frac{2 \times 6.6 \times 20}{40} = 6.6$

Q. 20ml of 0.2MAl2​(SO4​)3​ is mixed with 20ml of 6.6MBaCl2​, the concentration of Cl ion in solution is