20 cm3 of xM solution of Hcl is exactly neutralised by 40 cm3 of 0.05 M NaOH solution, the pH of HCl solution is

Question

20 cm3 of xM solution of Hcl is exactly neutralised by 40 cm3 of 0.05 M NaOH solution, the pH of HCl solution is (A) 1.0 (B) 2 (C) 1.5 (D) 2.5. 1

Tardigrade Admin · Accepted Answer

Moles of NaOH =0.05×40×10-3 Moles o f HCl =20×10-3× x 0.05× 40×10-3=20× x×10-3 or x=(0.05×40/20)=0.1 or 1×10-1 ∴ [HCl]=[H3O+]=1×10-1 ∴ PH=-log(1×10-1)=1

Q. 20cm3 of xM solution of Hcl is exactly neutralised by 40 cm3 of 0.05 M NaOH solution, the pH of HCl solution is

1.0

2

1.5

2.5. 1

Moles of NaOH=0.05×40×10−3 Moles o f HCl =20×10−3×x 0.05×40×10−3=20×x×10−3 or x=200.05×40​=0.1 or 1×10−1 ∴[HCl]=[H3​O+]=1×10−1 ∴PH=−log(1×10−1)=1

Q. $20 c m^{3}$ of xM solution of Hcl is exactly neutralised by 40 $c m^{3}$ of 0.05 M NaOH solution, the pH of HCl solution is