2 k mol of hydrogen at NTP expands isobarically to twice its initial volume. The change in its internal energy is (Cv=. 10 kJ / kg . K and atm pressure =1 × 105 N / m 2 )

Question

2 k mol of hydrogen at NTP expands isobarically to twice its initial volume. The change in its internal energy is (Cv=. 10 kJ / kg . K and atm pressure =1 × 105 N / m 2 ) (A) 10.9 MJ (B) 9.10 MJ (C) 109 MJ (D) 1.09 MJ

Tardigrade Admin · Accepted Answer

Δ U=n Cv Δ T=2 × 103 × 20 × 273=10.9 MJ

Q. $2 k m o l$ of hydrogen at NTP expands isobarically to twice its initial volume. The change in its internal energy is $(C_{v} =$ $10 k J / k g . K$ and atm pressure $= 1 \times 1 0^{5} N / m^{2}$ )

$10.9 M J$

$9.10 M J$

$109 M J$

$1.09 M J$

$Δ U = n C_{v} Δ T = 2 \times 1 0^{3} \times 20 \times 273 = 10.9 M J$

Q. 2kmol of hydrogen at NTP expands isobarically to twice its initial volume. The change in its internal energy is (Cv​= 10kJ/kg.K and atm pressure =1×105N/m2 )

10.9MJ

9.10MJ

109MJ

1.09MJ