2 g sample containing Na2CO3 and NaHCO3 loses 0.248 g of mass when heated at 300°C. At this temperature NaHCO3 decomposes to give sodium carbonate in the given sample. What is the % compostion of the mixture?

Question

2 g sample containing Na2CO3 and NaHCO3 loses 0.248 g of mass when heated at 300°C. At this temperature NaHCO3 decomposes to give sodium carbonate in the given sample. What is the % compostion of the mixture? (A) NaHCO3 16.8 %, Na2CO3 83.2 % (B) NaHCO3 33.5 %, Na2CO3 66.5 % (C) NaHCO3 83.2 %, Na2CO3 16.8 % (D) NaHCO3 66.5 %, Na2CO3 33.5 %

Tardigrade Admin · Accepted Answer

Weight of the mixture (NaHCO3 + Na2CO3) = 2 g underset168 g2NaHCO3 xrightarrowΔ, 300°C Na2CO3 + underbraceH2O uparrow + CO2 uparrow62 g Let mixture contain x g of NaHCO3, then, Wt. loss from x g of NaHCO3 ⇒ (62/168) × x = 0.248 g ⇒ x = 0.67 g x = (0.248 × 168/62) = 0.67 g Then NaHCO3 in sample = 0.67 g % NaHCO3 = (0.67/2) × 100 = 33.5 % and % Na2CO3 = 100 - 33.5 = 66.5 %

Q. $2 g$ sample containing $N a_{2} C O_{3}$ and $N a H C O_{3}$ loses $0.248 g$ of mass when heated at $30 0^{\circ} C$ . At this temperature $N a H C O_{3}$ decomposes to give sodium carbonate in the given sample. What is the $%$ compostion of the mixture?

$N a H C O_{3} 16.8%, N a_{2} C O_{3} 83.2%$

$N a H C O_{3} 33.5%, N a_{2} C O_{3} 66.5%$

$N a H C O_{3} 83.2%, N a_{2} C O_{3} 16.8%$

$N a H C O_{3} 66.5%, N a_{2} C O_{3} 33.5%$

Q. 2g sample containing Na2​CO3​ and NaHCO3​ loses 0.248g of mass when heated at 300∘C. At this temperature NaHCO3​ decomposes to give sodium carbonate in the given sample. What is the % compostion of the mixture?

NaHCO3​16.8%,Na2​CO3​83.2%

NaHCO3​33.5%,Na2​CO3​66.5%

NaHCO3​83.2%,Na2​CO3​16.8%

NaHCO3​66.5%,Na2​CO3​33.5%

Q. $2 g$ sample containing $N a_{2} C O_{3}$ and $N a H C O_{3}$ loses $0.248 g$ of mass when heated at $30 0^{\circ} C$ . At this temperature $N a H C O_{3}$ decomposes to give sodium carbonate in the given sample. What is the $%$ compostion of the mixture?

$N a H C O_{3} 16.8%, N a_{2} C O_{3} 83.2%$

$N a H C O_{3} 33.5%, N a_{2} C O_{3} 66.5%$

$N a H C O_{3} 83.2%, N a_{2} C O_{3} 16.8%$

$N a H C O_{3} 66.5%, N a_{2} C O_{3} 33.5%$