1M aqueous solution of AgNO3 , Cu((NO)3)2 and Au((NO)3)3 are electrolyzed, the same amount of electricity passes through each solution. If 0.1mol of solid Cu is formed then how many moles of Ag and Au are formed?

Question

1M aqueous solution of AgNO3 , Cu((NO)3)2 and Au((NO)3)3 are electrolyzed, the same amount of electricity passes through each solution. If 0.1mol of solid Cu is formed then how many moles of Ag and Au are formed? (A) 0.1molAg,0.1molAu (B) 0.05molAg,0.075molAu (C) 0.5molAg,0.15molAu (D) 0.2molAg,0.067molAu

Tardigrade Admin · Accepted Answer

Here, eq. of Ag=eq. of Cu=eq. of Au ⇒ 1× nAg=2× 0.1mol=3× nAu ∴ nAg=0.2mol and nAu=0.067mol

Q. $1 M$ aqueous solution of $A g N O_{3}$ , $C u ((NO)_{3})_{2}$ and $A u ((NO)_{3})_{3}$ are electrolyzed, the same amount of electricity passes through each solution. If $0.1 m o l$ of solid $C u$ is formed then how many moles of $A g$ and $A u$ are formed?

$0.1 m o l A g, 0.1 m o l A u$

$0.05 m o l A g, 0.075 m o l A u$

$0.5 m o l A g, 0.15 m o l A u$

$0.2 m o l A g, 0.067 m o l A u$

Here, $e q .$ of $A g = e q .$ of $C u = e q .$ of $A u$
$\Rightarrow 1 \times n_{A g} = 2 \times 0.1 m o l = 3 \times n_{A u}$
$∴ n_{A g} = 0.2 m o l$ and $n_{A u} = 0.067 m o l$

Q. 1M aqueous solution of AgNO3​ , Cu((NO)3​)2​ and Au((NO)3​)3​ are electrolyzed, the same amount of electricity passes through each solution. If 0.1mol of solid Cu is formed then how many moles of Ag and Au are formed?

0.1molAg,0.1molAu

0.05molAg,0.075molAu

0.5molAg,0.15molAu

0.2molAg,0.067molAu