Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
12 g of urea is dissolved in 1 L of water and 68.4 g of sucrose is dissolved in 1 L of water. The lowering of vapour pressure of urea is
Q. 12 g of urea is dissolved in 1 L of water and 68.4 g of sucrose is dissolved in 1 L of water. The lowering of vapour pressure of urea is
3688
222
Solutions
Report Error
A
equal to sucrose
40%
B
greater than sucrose
20%
C
less than sucrose
20%
D
double that of sucrose
20%
Solution:
12
g
urea
=
60
12
=
0.2
m
o
l
,
68.4
g
sucrose
=
342
68.4
=
0.2
m
o
l
As mole fraction of solute is same hence, lowering of vapour pressure is same.