100 mL of PH3 on heating forms P and H2. The volume change in the reaction is

Question

100 mL of PH3 on heating forms P and H2. The volume change in the reaction is (A) an increase of 50 mL (B) an increase of 100 mL (C) an increase of 150 mL (D) a decrease of 50 mL

Tardigrade Admin · Accepted Answer

underset4 vol 4PH3(g) leftharpoons 4P(s) + underset6 vol6H2 (g) 100 mL (100 × 6/4) = 150 mL Change in volume = (150 - 100) mL = 50 mL

Q. $100 m L$ of $P H_{3}$ on heating forms $P$ and $H_{2}$ . The volume change in the reaction is

an increase of 50 mL

an increase of 100 mL

an increase of 150 mL

a decrease of 50 mL

$4 v o l 4 P H_{3} (g) ⇌ 4 P (s) + 6 v o l 6 H_{2} (g)$
$100 m L \frac{100 \times 6}{4} = 150 m L$
Change in volume $= (150 - 100) m L = 50 m L$

Q. 100mL of PH3​ on heating forms P and H2​. The volume change in the reaction is