100 cc of 0.6 text N text H2SO4 and 200 cc of 0.3 text N text HCl were mixed together. The normality of the solution will be

Question

100 cc of 0.6 text N text H2SO4 and 200 cc of 0.3 text N text HCl were mixed together. The normality of the solution will be (A) 0.2 N (B) 0.4 N (C) 0.8 N (D) 0.6 N

Tardigrade Admin · Accepted Answer

Normality of the mixed solution =(N1V1+N2V2/V1+V2)=(0.6× (100/1000)+0.3× (200/1000)/(100+200)1000) =(0.6× 0.1+0.3× 0.2/0.3) =(0.06+0.06/0.3)=(0.12/0.3)=0.4N

Q. 100 cc of $0.6 N H_{2} S O_{4}$ and 200 cc of $0.3 N H Cl$ were mixed together. The normality of the solution will be

0.2 N

0.4 N

0.8 N

0.6 N

Normality of the mixed solution $= \frac{N _{1} V _{1} + N _{2} V _{2}}{V _{1} + V _{2}} = \frac{0.6 \times \frac{100}{1000} + 0.3 \times \frac{200}{1000}}{\frac{100 + 200}{1000}}$ $= \frac{0.6 \times 0.1 + 0.3 \times 0.2}{0.3}$ $= \frac{0.06 + 0.06}{0.3} = \frac{0.12}{0.3} = 0.4 N$

Q. 100 cc of 0.6NH2​SO4​ and 200 cc of 0.3NHCl were mixed together. The normality of the solution will be