100 c.c. of N / 10 NaOH solution is mixed with 100 c.c. of N / 5 HCl solution and the whole volume is made to 1 litre. The pH of the resulting solution will be

Question

100 c.c. of N / 10 NaOH solution is mixed with 100 c.c. of N / 5 HCl solution and the whole volume is made to 1 litre. The pH of the resulting solution will be (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

We know, for an aicd base mixture, N 3( V 1+ V 2)=| N 1 V 1- N 2 V 2| Where, N3(V1+V2)= Number of gram equivalents of HCl (∵ Acid is in excess) Now, g. equivalents of HCl =|0.1 × 0.1-0.1 × 0.2|=0.01 ∴ Number of moles =( text Number of g text equivalents /n text factor of HCl ) =(0.01/1)=0.01 ∴ underset0.01HCl → underset0.01H+ + underset0.01Cl ominus ⇒ PH = - log10 [H+] = 2

Q. 100c.c. of N/10NaOH solution is mixed with 100c.c. of N/5HCl solution and the whole volume is made to 1 litre. The pH of the resulting solution will be

1

2

3

4

Q. $100 c . c .$ of $N /10 N a O H$ solution is mixed with $100 c . c$ . of $N /5 H Cl$ solution and the whole volume is made to $1$ litre. The $p H$ of the resulting solution will be