10 g of NaOH is dissolved in 500 ml of aqueous solution. Calculate the molarity of this solution? (Formula weight of NaOH=40)

Question

10 g of NaOH is dissolved in 500 ml of aqueous solution. Calculate the molarity of this solution? (Formula weight of NaOH=40) (A) 0.5 × 10-3 M (B) 0.4 M (C) 0.25 × 10-3 M (D) 0.5 M

Tardigrade Admin · Accepted Answer

∴ Molarity =( text Mass of solute ( text in g L-1)/ text Molar of solute ( text in g mol-1)) =((10/500) × 1000/40) M=0.5 M

Q. $10 g$ of $N a O H$ is dissolved in $500 m l$ of aqueous solution. Calculate the molarity of this solution? (Formula weight of $N a O H = 40$ )

$0.5 \times 1 0^{- 3} M$

$0.4 M$

$0.25 \times 1 0^{- 3} M$

$0.5 M$

$∴$ Molarity $= \frac{Mass of solute ( in g L ^{- 1} )}{Molar of solute ( in g m o l ^{- 1} )}$
$= \frac{\frac{10}{500} \times 1000}{40} M = 0.5 M$

Q. 10g of NaOH is dissolved in 500ml of aqueous solution. Calculate the molarity of this solution? (Formula weight of NaOH=40)

0.5×10−3M

0.4M

0.25×10−3M

0.5M