Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
1-Penten-4-yne reacts with bromine at -80° C to produce
Q. 1-Penten-4-yne reacts with bromine at
−
8
0
∘
C to produce
502
152
NTA Abhyas
NTA Abhyas 2022
Report Error
A
4,4,5,5-Tetrabromopentene
B
1,2-Dibromo-1,4-pentadiene
C
1,1,2,2,4,5-Hexabromopentane
D
4,5-dibromopentyne
Solution:
1-Penten-4-yne reacts with bromine at
−
8
0
∘
C to produce 4,5-dibromopentyne as follows
C
H
2
=
C
H
−
C
H
2
−
C
≡
C
H
+
B
r
2
→
−
8
0
∘
C
H
2
B
r
−
C
H
B
r
−
C
H
2
−
C
≡
C
H