1.30 cm 3 of N 2 gas at STP is adsorbed per gram of silica gel. The area occupied by nitrogen molecule is 0.16 nm 2. What is the surface area per gram of silica gel? (N A =6.023 × 1023)

Question

1.30 cm 3 of N 2 gas at STP is adsorbed per gram of silica gel. The area occupied by nitrogen molecule is 0.16 nm 2. What is the surface area per gram of silica gel? (N A =6.023 × 1023) (A) 1.6 m 2 / g (B) 5.568 m 2 / g (C) 3.48 m 2 / g (D) 4.42 m 2 / g

Tardigrade Admin · Accepted Answer

Number of N 2 molecules adsorbed per gram of silica gel =(1.30 × 6 × 1023/22400)=3.48 × 1019 Area of cross section of molecule =0.16 nm 2=1.6 × 10-19 m 2 Surface area covered per gram of silica gel =1.6 × 10-19 × 3.48 × 1019=5.568 m 2

Q. $1.30 c m^{3}$ of $N_{2}$ gas at STP is adsorbed per gram of silica gel. The area occupied by nitrogen molecule is $0.16 n m^{2}$ . What is the surface area per gram of silica gel? $(N_{A} = 6.023 \times 1 0^{23})$

$1.6 m^{2} / g$

$5.568 m^{2} / g$

$3.48 m^{2} / g$

$4.42 m^{2} / g$

Q. 1.30cm3 of N2​ gas at STP is adsorbed per gram of silica gel. The area occupied by nitrogen molecule is 0.16nm2. What is the surface area per gram of silica gel? (NA​=6.023×1023)

1.6m2/g

5.568m2/g

3.48m2/g

4.42m2/g

Number of N2​ molecules adsorbed per gram of silica gel =224001.30×6×1023​=3.48×1019 Area of cross section of molecule =0.16nm2=1.6×10−19m2 Surface area covered per gram of silica gel =1.6×10−19×3.48×1019=5.568m2

Q. $1.30 c m^{3}$ of $N_{2}$ gas at STP is adsorbed per gram of silica gel. The area occupied by nitrogen molecule is $0.16 n m^{2}$ . What is the surface area per gram of silica gel? $(N_{A} = 6.023 \times 1 0^{23})$

$1.6 m^{2} / g$

$5.568 m^{2} / g$

$3.48 m^{2} / g$

$4.42 m^{2} / g$