1.2 g of organic compound on Kjeldahlization liberates ammonia which consumes 30 cm3 of 1 N HCl. The percentage of nitrogen in the organic compound is

Question

1.2 g of organic compound on Kjeldahlization liberates ammonia which consumes 30 cm3 of 1 N HCl. The percentage of nitrogen in the organic compound is (A) 30 (B) 35 (C) 46.67 (D) 20.8

Tardigrade Admin · Accepted Answer

Percentage of nitrogen =(1.4 × N text of acid × text Vol. used with NH 3/ text Weight of organic compound ) =(1.4 × 1 × 30/1.2) =35

Q. $1.2 g$ of organic compound on Kjeldahlization liberates ammonia which consumes $30 c m^{3}$ of $1 N H Cl$ . The percentage of nitrogen in the organic compound is

30

35

46.67

20.8

Percentage of nitrogen $= \frac{1.4 \times N of acid \times Vol. used with N H _{3}}{Weight of organic compound}$

$= \frac{1.4 \times 1 \times 30}{1.2}$

$= 35$

Q. 1.2g of organic compound on Kjeldahlization liberates ammonia which consumes 30cm3 of 1NHCl. The percentage of nitrogen in the organic compound is

30

35

46.67

20.8

Percentage of nitrogen = Weight of organic compound 1.4×N of acid × Vol. used with NH3​​ =1.21.4×1×30​ =35

Q. $1.2 g$ of organic compound on Kjeldahlization liberates ammonia which consumes $30 c m^{3}$ of $1 N H Cl$ . The percentage of nitrogen in the organic compound is

Percentage of nitrogen $= \frac{1.4 \times N of acid \times Vol. used with N H _{3}}{Weight of organic compound}$

$= \frac{1.4 \times 1 \times 30}{1.2}$

$= 35$