Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
1.2.3 + 2.3.4 + ....... + n(n+1) (n+2) =
Q.
1.2.3
+
2.3.4
+
.......
+
n
(
n
+
1
)
(
n
+
2
)
=
2090
289
Principle of Mathematical Induction
Report Error
A
4
n
(
n
+
1
)
(
n
+
2
)
B
4
n
(
n
+
1
)
(
n
+
2
)
(
n
+
3
)
C
3
n
(
n
+
1
)
(
n
+
2
)
D
6
n
(
n
+
1
)
(
n
+
2
)
(
n
+
3
)
Solution:
Put
n
=
1
and verify the options