0.24 g of an organic compound gave 0.22 g O2 on complete combustion. If it contains 1.66% hydrogen, then the percentage of C and O will be

Question

0.24 g of an organic compound gave 0.22 g O2 on complete combustion. If it contains 1.66% hydrogen, then the percentage of C and O will be (A) 12.5 and 36.6 (B) 25 and 75 (C) 25 and 36.6 (D) 25 and 80

Tardigrade Admin · Accepted Answer

% of C=(12/44)×( textMass of CO2/ textMass of substance )×100 =(12×0.22/44×0.24)×100=25 ; C=25, H=1.66 Total =26.6=100-26.6=73.4

Q. $0.24 g$ of an organic compound gave $0.22 g$ $O_{2}$ on complete combustion. If it contains 1.66% hydrogen, then the percentage of C and O will be

12.5 and 36.6

25 and 75

25 and 36.6

25 and 80

$%$ of $C = \frac{12}{44} \times \frac{Mass of C O _{2}}{Mass of substance} \times 100$
$= \frac{12 \times 0.22}{44 \times 0.24} \times 100 = 25; C = 25$ ,
$H = 1.66$
Total $= 26.6 = 100 - 26.6 = 73.4$

Q. 0.24g of an organic compound gave 0.22g O2​ on complete combustion. If it contains 1.66% hydrogen, then the percentage of C and O will be