0.02 mole of [Co(NH3)5Br]Cl2 and 0.02 mole of [Co(NH3)5Cl]SO4 are present in 200 cc of a solution X. The number of moles of the precipitates Y and Z that are formed when the solution X is treated with excess silver nitrate and excess barium chloride are respectively

Question

0.02 mole of [Co(NH3)5Br]Cl2 and 0.02 mole of [Co(NH3)5Cl]SO4 are present in 200 cc of a solution X. The number of moles of the precipitates Y and Z that are formed when the solution X is treated with excess silver nitrate and excess barium chloride are respectively (A) 0.02, 0.02 (B) 0.01, 0.02 (C) 0.02, 0.04 (D) 0.04, 0.02

Tardigrade Admin · Accepted Answer

underset1 mol[ Co ( NH 3)5 Br ] Cl 2+2 AgNO 3 longrightarrow

underset1 mol[Co(NH3)5Cl]SO4+BaCl2 →

0.02, 0.02

0.01, 0.02

0.02, 0.04

0.04, 0.02

0.02, 0.01

$1 m o l [C o (N H_{3})_{5} B r] C l_{2} + 2 A g N O_{3} ⟶$

$1 m o l [C o (N H_{3})_{5} Cl] S O_{4} + B a C l_{2} \to$

Q. 0.02 mole of [Co(NH3​)5​Br]Cl2​ and 0.02 mole of [Co(NH3​)5​Cl]SO4​ are present in 200cc of a solution X. The number of moles of the precipitates Y and Z that are formed when the solution X is treated with excess silver nitrate and excess barium chloride are respectively