Q.
Two rings of radius R and nR made of same material have the ratio of moment of inertia about an axis passing through centre in 1:8. The value of n is
Ratio of moment of inertia of the rings I2I1=(M2M1)(R2R1)2=(λL2λL1)2(R2R1)2 =(2πnR2πR)(nRR)2 [λ= linear density of wire = constant ] ⇒L2L1+n31+81 (given) ∴n3=8 ⇒n=2