The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)

Question

The energy of an electron in the first Bohr orbit of H-atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are) (A) -3.4 eV (B) -4.2 eV (C) -6.8 eV (D) +6.8 eV

Tardigrade Admin · Accepted Answer

The energy of an electron in a Bohr atom is expressed as

E_{n} = - \frac{k Z ^{2}}{n ^{2}}

where,

k =

Constant,

Z =

Atomic number,

n =

Orbit number

= - 13.6 e V

for

H (n = 1)

when

n = 2, E_{2} = \frac{- 13.6}{2 ^{2}} e V = - 3.40 e V

(

n

can have only integral value

1, 2, 3, \dots\dots \infty

)

Q. The energy of an electron in the first Bohr orbit of H-atom is -13.6eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)

-3.4 eV

-4.2 eV

-6.8 eV

+6.8 eV

The energy of an electron in a Bohr atom is expressed as En​=−n2kZ2​ where, k= Constant, Z= Atomic number, n= Orbit number =−13.6eV for H(n=1) when n=2,E2​=22−13.6​eV=−3.40eV ( n can have only integral value 1,2,3,……∞ )

Q. The energy of an electron in the first Bohr orbit of H-atom is - $13.6 e V$ . The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)