A particle is projected with velocity u at angle θ with horizontal at t = 0. What is the magnitude of change in the velocity of the particle when it is at maximum height?

Question

A particle is projected with velocity u at angle θ with horizontal at t = 0. What is the magnitude of change in the velocity of the particle when it is at maximum height? (A) (u cos θ/2) (B) u cos θ (C) u sin θ (D) none of these

Tardigrade Admin · Accepted Answer

vecu i=u cos θ hati+u sin θ hatj vecuf=u cos θ hati Δ vecu= vecuf- vecui=-u sin θ hatj |Δ vecu|=u sin θ

Q. A particle is projected with velocity u at angle $θ$ with horizontal at $t = 0.$ What is the magnitude of change in the velocity of the particle when it is at maximum height?

$\frac{u cos θ}{2}$

u cos $θ$

u sin $θ$

none of these

$u_{i} = u cos θ \hat{i} + u s in θ \hat{j}$

$u_{f} = u cos θ \hat{i}$

$Δ u = u_{f} - u_{i} = - u s in θ \hat{j}$

$∣ Δ u ∣ = u s in θ$

Q. A particle is projected with velocity u at angle θ with horizontal at t=0. What is the magnitude of change in the velocity of the particle when it is at maximum height?

2ucosθ​

u cos θ

u sin θ