A packet contains silver powder of mass 20.23 g ± 0.01 g Some of the powder of mass 5.75 g ± 0.01 g is taken out from it. The mass of the powder left back is

Question

A packet contains silver powder of mass 20.23 g ± 0.01 g Some of the powder of mass 5.75 g ± 0.01 g is taken out from it. The mass of the powder left back is (A) 14.48 g ± 0.00 g (B) 14.48 ± 0.02 g (C) 14.5 g ± 0.1 g (D) 14.5 g ± 0.2 g

Tardigrade Admin · Accepted Answer

m1=20.23 g ± 0.01 g m2=(5.75 ± 0.01) g m1-m2=[(20.23-5.75) ± 0.02] g Δ m=(14.48 ± 0.02) g

Q. A packet contains silver powder of mass $20.23 g \pm 0.01 g$ Some of the powder of mass $5.75 g \pm 0.01 g$ is taken out from it. The mass of the powder left back is

$14.48 g \pm 0.00 g$

$14.48 \pm 0.02 g$

$14.5 g \pm 0.1 g$

$14.5 g \pm 0.2 g$

$m_{1} = 20.23 g \pm 0.01 g$
$m_{2} = (5.75 \pm 0.01) g$
$m_{1} - m_{2} = [(20.23 - 5.75) \pm 0.02] g$
$Δ m = (14.48 \pm 0.02) g$

Q. A packet contains silver powder of mass 20.23g±0.01g Some of the powder of mass 5.75g±0.01g is taken out from it. The mass of the powder left back is

14.48g±0.00g

14.48±0.02g

14.5g±0.1g

14.5g±0.2g