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Q. The equivalent weight of $MnSO _{4}$ is equal to its molecular weight when it is converted to

The d-and f-Block Elements

Solution:

$\overset{2+}{2 MnSO _{4}} \longrightarrow \overset{3+}{Mn _{2} O _{3}}$
$n$-factor $=1$
$\therefore $ Molecular weight = Equivalent weight.