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  4. A packet contains silver powder of mass 20.23 g ± 0.01 g Some of the powder of mass 5.75 g ± 0.01 g is taken out from it. The mass of the powder left back is

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Q. A packet contains silver powder of mass $20.23\, g \pm 0.01\, g$ Some of the powder of mass $5.75\, g \pm 0.01\, g$ is taken out from it. The mass of the powder left back is

Physical World, Units and Measurements

Solution:

$m_{1}=20.23 g \pm 0.01\, g$
$m_{2}=(5.75\, \pm 0.01) g$
$m_{1}-m_{2}=[(20.23-5.75) \pm 0.02] g$
$\Delta m=(14.48 \pm 0.02) g$